We roll a fair 6-sided die 5 times. What is the probability that we get a 6 in at most 2 of the rolls?
Amanita, let's break down the problem step by step:
Step 1: Understand the problem
We roll a fair 6-sided die 5 times. We want the probability of getting a 6 in at most 2 of those rolls. "At most 2" means we can get a 6 zero times, one time, or two times across the 5 rolls.
Step 2: Choose the proper probability model
This scenario can be described using the binomial probability formula, because each roll is independent and there is only "success" (getting a 6) or "failure" (getting anything else) in each roll.
The binomial probability formula is:
where:
- = total number of trials (rolls) = 5
- = number of desired successes (times we get a 6) = 0, 1, or 2
- = probability of success on a single roll =
Step 3: Write the probability expression for "at most 2 sixes"
We need:
Step 4: Calculate each term using the binomial formula
Let's substitute the values for each case:
- For :
- For :
- For :
Step 5: Sum all the probabilities to find the answer
Now, I will calculate and sum the values for , , and . Amanita, here is how we solve the problem step by step:
- We use the binomial probability formula to find the probability of getting a 6 in at most 2 rolls when we roll a die 5 times.
- We calculate the probability for getting 0, 1, or 2 sixes, and add them up.
- The formula used is:
for . 4. Adding these probabilities, we get:
Final Answer:
The probability that you get a 6 in at most 2 of the 5 rolls is