We roll a fair 6-sided die 5 times. What is the probability that we get a 6 in at most 2 of the rolls?
Amanita, let’s break down the problem and solve it step by step!
Step 1: Understanding the Problem
We roll a fair 6-sided die 5 times. We want to find the probability that the number 6 appears in at most 2 of those rolls. This means that 6 can appear 0, 1, or 2 times in the five rolls.
Step 2: Recognizing the Probability Model
Each roll can be considered a "success" (rolling a 6) or "failure" (not rolling a 6). The probability of rolling a 6 on any one roll is:
and the probability of not rolling a 6 is:
Given 5 rolls, and the event "rolling a 6" can happen 0, 1, or 2 times, this follows a binomial distribution with parameters and .
Step 3: Writing the General Formula
The probability of getting exactly sixes in 5 rolls is:
where is the number of ways to choose successful rolls out of 5.
Step 4: Find the Probability for Each Case
We want , which means we sum the probabilities for :
Let’s calculate each term.
Step 5: Substitute and Calculate Each Term
- For :
- For :
- For :
Now, I will calculate each probability and then find their sum.
Step 6: Sum the Probabilities
After finding each probability, we add them:
I’ll now calculate all needed values and provide the answer. Amanita, here is the final answer:
The probability that you get a 6 in at most 2 of the 5 rolls of a fair 6-sided die is
This means that if you roll a die 5 times, in most cases (about 50% of the time), you will get a 6 no more than 2 times.